1186 . A student loses 1 mark for every wrong answer and scores 2 marks for every correct answer . If he answers all the 60 questions in an exam and scores 39 marks , how many of them were correct ?

A. 33
B. 31
C. 27
D. 37

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Answer: Option A

Explanation:

ধরি, সঠিক উত্তর দেওয়ার প্রশ্ন সংখ্যা x
⸫ 2x – (60 – x) × 1 = 39
⇒ 2x – 60 + x = 39
⇒ 3x = 99 ⸫ x = 33

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Bangladesh Bank - Assistant Director - 2015

A. 27
B. 31
C. 33
D. 37

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Answer: Option C

Explanation:

ধরি, সঠিক উত্তর দেওয়ার প্রশ্ন সংখ্যা x
⸫ 2x – (60 – x) × 1 = 39
⇒ 2x – 60 + x = 39
⇒ 3x = 99

⸫ x = 33

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1188 . A student makes twice as many mistake as he makes correct answer in an exam. For each wrong answer $\frac{1}{4}$ is deducted from his score. If he scores 20 in the exam, how many questions did he attempt in the exam? (একজন শিক্ষার্থী পরীক্ষায় সঠিক উত্তরের চেয়ে দ্বিগুণ ভুল করে। তার স্কোর থেকে প্রতিটি ভুল উত্তরের জন্য $\frac{১}{৪}$ কাটা হয়। যদি সে পরীক্ষায় ২০ নম্বর পায়, তাহলে সে পরীক্ষায় কতটি প্রশ্নের উত্তর করেছিল?)

A. 60
B. 120
C. 180
D. 200

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Answer: Option B

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Dutch Bangla Bank || Sales Manager (18-09-2024) || 2024

A. 34%
B. 44%
C. 54%
D. 64%

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Answer: Option D

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উত্তরা ব্যাংক | অ্যাসিস্ট্যান্ট অফিসার | 23-07-2022

A. 57
B. 76
C. 77
D. 78

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Answer: Option C

Explanation:

2nd Test's Marks = 2x82 - 80 = 84
3rd Test's Marks = 3x78 - 2x2 = 234 - 164 = 70
The average of his 2nd and 3rd tests' marks = (84 + 70)/2 = 154/2 = 77.

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Bangladesh Bank - Assistant Director - 2001

A. 44
B. 45
C. 66
D. 77

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Answer: Option C

Explanation:

Calculate the total marks for all 8 papers, assuming each paper is out of 100 marks: Total Marks = 8 papers * 100 marks/paper = 800 marks

Calculate 55% of the total marks to find the student's overall score: Overall Score = 55% of Total Marks Overall Score = (55/100) * 800 = 0.55 * 800 = 440 marks

Calculate the marks scored in English, which is 15% of the total marks scored in all 8 papers: Marks in English = 15% of Overall Score Marks in English = (15/100) * 440 = 0.15 * 440 = 66 marks

So, the student scored 66 marks in English.

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সমন্বিত পাঁচ ব্যাংক || অফিসার ক্যাশ - 06.11.2021

1192 . A student walks from his house at a speed of $2 \frac{1}{2}$ K per hour and reaches his school 6 minutes late. The next day he increases his speed by 1 km per hour and reaches 6 minutes before school time. How far is the school from his house?

A. $1 \frac{1}{4} k m$
B. $1 \frac{3}{4} k m$
C. $2 \frac{1}{4} k m$
D. $2 \frac{3}{4} k m$

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Answer: Option B

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Janata Bank PLC || Officer (Rural Credit) (27-10-2023) || 2023

A. 7
B. 17
C. 31
D. 3

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Answer: Option A

Explanation:

(3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x)/12 = 12

137 + x /12 = 12

x = 144 - 137

x = 7

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Bangladesh Bank - Officer(Cash) - 2016

A. 7
B. 3
C. 17
D. 31

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Answer: Option A

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1195 . A student who secures 20% marks in an examination fails by 30 marks another student secures 32% marks gets 42 marks more than those required to pass. The percentage of marks required to pass is--

A. 28%
B. 30%
C. 20%
D. 25%

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Answer: Option D

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1196 . A sum fetches a simle interest of tk.6000 at the rate of 5% pa.in 6years. what would be the compound interest earned at the same rate of interest and the same principal in 2 years?

A. tk.2050
B. tk.2500
C. tk.2125
D. tk.2245

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Answer: Option A

Explanation:

The sum = Tk. (6000 × 100)/(5 × 6) = Tk. 20000
Compound Interest = (20000 × 105/100 × 105/100) – 20000 = Tk. 2050. Ans: A

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অফিসার (ক্যাশ) নিয়োগ পরীক্ষা- ১২-১০-২০১৮ ||

A. 5%
B. 8%
C. 12%
D. 15%

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Answer: Option C

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1198 . A sum of money amounts to Tk 460 in 3 years and to Tk 500 in five years. Find the rate percent per amount

A. 5 Tk
B. 10 Tk
C. 15 Tk
D. 25 Tk

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Answer: Option A

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1199 . A sum of money at simple interest amounts to Tk.2240 in 2 years and Tk.2600 in 5 years, the sum is--

A. 2120
B. 1880
C. 2000
D. cannot be calculated

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Answer: Option C

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1200 . A sum of money at simple interest amounts to TK. 5600 in 2 years and Tk. 6500 in 5 years at the rate of -

A. 4%
B. 3%
C. 5%
D. 6%

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Answer: Option D

Explanation:

To find the rate of simple interest, we can use the formula:

Simple Interest (SI) = (Principal * Rate * Time) / 100

We are given two different scenarios:

The money amounts to Tk. 5600 in 2 years.
The money amounts to Tk. 6500 in 5 years.

Let's use the first scenario to calculate the rate:

SI = (Principal * Rate * Time) / 100

5600 = (Principal * Rate * 2) / 100

Now, rearrange the formula to solve for the rate (R):

Rate (R) = (SI * 100) / (Principal * Time)

Rate (R) = (5600 * 100) / (Principal * 2)

Now, let's use the second scenario to calculate the rate:

SI = (Principal * Rate * Time) / 100

6500 = (Principal * Rate * 5) / 100

Again, rearrange the formula to solve for the rate (R):

Rate (R) = (SI * 100) / (Principal * Time)

Rate (R) = (6500 * 100) / (Principal * 5)

Now, let's compare the rates from both scenarios:

Rate in the first scenario (R1) = (5600 * 100) / (Principal * 2) Rate in the second scenario (R2) = (6500 * 100) / (Principal * 5)

Since both scenarios involve the same principal amount, we can compare the rates:

R1 / R2 = [(5600 * 100) / (Principal * 2)] / [(6500 * 100) / (Principal * 5)]

R1 / R2 = (5600 * 100 * 5) / (6500 * 100 * 2)

R1 / R2 = 28000 / 13000

R1 / R2 = 2.1538 (approximately)

So, the rate of interest is approximately 2.1538 times higher in the second scenario compared to the first scenario.

Now, let's calculate the rate in the second scenario (R2):

R2 = (Rate in the first scenario, R1) * 2.1538

R2 ≈ 6% (approximately)

Therefore, the rate of interest is approximately 6%.

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সমন্বিত ৭ ব্যাংক ও ১টি আর্থিক | সিনিয়র_অফিসার | 27-11-2021

1186 . A student loses 1 mark for every wrong answer and scores 2 marks for every correct answer . If he answers all the 60 questions in an exam and scores 39 marks , how many of them were correct ?

1187 . A student loses I mark for every wrong answer and scores 2 marks for every correct answer . If he answers all the 60 questions in an exam and scores 39 marks , how many of them were correct?

1189 . A student multiplied a number by 3/5 insted of 5/3. What is the percentage of error in the calculation?

1190 . A student scored 80 marks in his first test. After taking the third test, his average dropped from 82 to78 . What is the average of his 2nd and 3rd tests ?

1191 . A student scores 55% marks in 8 papers of 100 marks each. He scores 15% of his total marks in English. How much does he score in English?

1193 . A student was asked to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14, and x. He found the mean to be 12. What should be the number in place of x ?

1194 . A student was asked to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and p. He found the mean to be 12. What should be the number in place of p?

1195 . A student who secures 20% marks in an examination fails by 30 marks another student secures 32% marks gets 42 marks more than those required to pass. The percentage of marks required to pass is--

1196 . A sum fetches a simle interest of tk.6000 at the rate of 5% pa.in 6years. what would be the compound interest earned at the same rate of interest and the same principal in 2 years?

1197 . A sum of money amounts to Tk. 9800 after 5 years and Tk. 12005 after 8 years at the same rate of simple interest. The rate of interest per annual is:

1198 . A sum of money amounts to Tk 460 in 3 years and to Tk 500 in five years. Find the rate percent per amount

1199 . A sum of money at simple interest amounts to Tk.2240 in 2 years and Tk.2600 in 5 years, the sum is--

1200 . A sum of money at simple interest amounts to TK. 5600 in 2 years and Tk. 6500 in 5 years at the rate of -

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